Hasil integral (3x² + 6x – 8) batas atas 2 batas bawah -3 dx =

by

²₋₃

= (2³ + 3.2² – 8.2) – ((-3)³ + 3(-3)² – 8(-3))
= (8 + 12 – 16) – (–27 + 27 + 24)
= 4 – 24
= –20
  Diketahui f(x) = 2x + 5 dan g(x) = x − 1/x + 4, x ≠ -4,