u(x) = (1 – x)² maka
u՛(x) = 2(1 – x)¹(-1)
= -2(1 – x)
v(x) = 2x + 3 maka v՛(x) = 2
h(x) = u(x) + v(x)
h՛(x) = u՛(x)v(x) + u(x)v՛(x)
= -2(1 – x)(2x + 3) + (1 – x)² × 2
= -2(1 – x)[(2x + 3) – (1 – x)]
= -2(1 – x)(3x + 2)
= 2(x – 1)(3x + 2
Kaprikornus, h՛(x) = 2(x – 1)(3x + 2).