Sisa pembagian suku banyak oleh (2x² + x – 1) yaitu ….
P(x) = (4x² – 1) h(x) + 3x – 4
= (2x + 1)(2x – 1) h(x) + 3x – 4
P(1) = 3 _ 4 ₌ _ 5
2 2 2
P(x) = (x + 1)h(x) – 16
P(-1) = -16
P(x) = (2x² + x – 1) h(x) + ax + b
P(1) = 1 a + b = _ 5
2 2 2
P(-1) = -a + b = – 16 _
a = 9
a = 9 ➞ -9 + b = -16
b = -7
Jadi sisanya 9x – 7