Nilai Sigma 21 n=2 (5n – 6) = …

by

Jawab:

21
 Σ   (5n – 6) = 4 + 9 + 14 + … + 99
n=2                              n=20
S₂₀ = 20÷2 (4 + 99)
      = 10 (103)
      = 1030
  Nilai limit x mendekati 0 (1 – cos2x/x²) = ...