Pembahasan:
Cara 1:
lim 6 – 2x ₌ lim 2(3 – x)
x￫3 2x² – 9x + 9 x￫3 (2x – 3)(x – 3)
₌ lim –2
x￫3 (2x – 3)
= –2
2.3 – 3
= _ 2
3
Cara 2: L’hospital
lim 6 – 2x
x￫3 2x² – 9x + 9
⇒ f'(x) = –2 ; x = 3
(4x – 9)
⇒ –2 ₌ _ 2
4.3 – 9 3