Hasil ₁∫⁴ x + 2 dx
√x
= ₁∫⁴ (x/√x + 2/√x) dx
= ₁∫⁴ (x½ + 2x⁻½) dx
= [1x³/₂ + 2 × 1x½]⁴
³/₂ ½ ¹
= [⅔x√x + 4√x]⁴
¹
= (⅔ × 4 × √4 + 4 × √4) – (⅔ × 1 × √1 + 4 × 1)
= (16 ₊ 8) _ (2 ₊ 4)
3 3
= 40 _ 14 = 26
3 3 3
Jadi, Hasil ₁∫⁴ x + 2 dx = 26
√x 3