Integral (sin2x + 3cosx) batas atas ⅓π batas bawah 0 dx =

by

⅓π₀

= (-½cos2(π/3) + 3sinπ/3) – (-½cos0 + 3sin0)
= (-½(-½) + 3.½√3) – (-½.1 + 3.0)
= 1 ₊ 3√3 ₊ 1
   2    2        2
= 3 ₊ 3√3
   4    2
= 3 (1 + 2√3)
   4
  Nilai limit x mendekati 2 x² - 5x + 6/x² - 4 = ...