Integral (2x² + 4x – 3) batas atas 3 batas bawah 1 dx = 24/07/2022 by hadi wargamasyarakat ³₁ = [⅔(3³) + 2(3²) – 3(3)] – [⅔(1³) + 2(1²) – 3(1)] = [18 + 18 – 9] – [⅔ + 2 – 3] = 27 – ⅔ + 1 = 27⅓ Nilai sinus sudut antara bidang TPQ dengan bidang TRS