Hasil Integral 2x + 3 per akar 3x² + 9x – 1 = …

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Pembahasan:

⌠       2x + 3      dx = ∫(2x + 3)(3x² + 9x – 1)⁻¹/²
⌡ √3x² + 9x – 1
Menggunakan integral substitusi:
Misal: u = 3x² + 9x – 1
du = 6x + 9 dx
⅓du = 2x + 3 dx
∫ (2x + 3)(3x² + 9x – 1)⁻¹/² dx = ∫ ⅓u⁻¹/²
= ⅔u¹/² + C = ⅔√3x² + 9x – 1 + C
  Simpangan baku data 6, 4, 5, 6, 5, 7, 8, 7