b = ³log2 √2 + 1 _ ⁶log8
⁴log9 ⁶log3
Nilai a = ….
b
Jawaban:
a = ³log² 6 – ³log² 2 – 2 ⁹log 6
= (³log6)² – (³log2)² – 2 . 3²log 6
= (³log3 + ³log2)² – (³log2)² – (³log3 + ³log2)
= 1 + 2 . ³log2 + (³log 2)² – (³log2)² – 1 – ³log2
= ³log2
b = ³log2 √2 + 1 _ ⁶log8
⁴log9 ⁶log3
= ³log23/2 + ⁹log4 – ³log8
= 3 . ³log2 – ³log2 – 3.³log2
2
= _ 1 ³log2
2
Jadi: a = ³log2
b -1/2 ³log2