Pembahasan:
f(x) = x³ + 3x² + 8
Nilai maksimum?
Maksimum dicapai saat f'(x) = 0
• Titik stasioner f'(x) = 0
3x² + 6x = 0
3x(x + 2) = 0
x = 0 atau x = –2
• f(0) = 0 + 0 + 8 = 8
f(–2) = (–2)³ + 3(–2)² + 8
= –8 + 12 + 8 = 12
Makara nilai maksimum fungsi yakni 12