Pembahasan:
2, 3, 4, 5, 6
Simpangan baku?
x︦ = 2 + 3 + 4 + 5 + 6 = 20 = 4
5 5
S = ⎷Σ(xi – x︦)²
n
= √(2-4)² + (3-4)² + (4-4)² + (5-4)² + (6-4)²
5
= √4 + 1 + 0 + 1 + 4
5
= √10
5
= √2