2 Log 24 + 2 Log 3 – 2 Log 9

Daftar Isi

2 log 24 + 2 log 3 – 2 log 9

=2log24.3/9
=2log72/9
=2log8
=3

Penjelasan dgn tindakan:

Logaritma

[tex] ^ 2 log \: 24 + ^ 2 log \: 3 – ^ 2 log \: 9[/tex]

[tex] = ^ 2 log \: (24 \times 3 \div 9)[/tex]

[tex] = ^ 2 log \: 8[/tex]

[tex] = ^ 2 log \: 2 ^ 3 [/tex]

[tex] = 3 \times ^ 2 log \: 2[/tex]

[tex] = 3 \times 1[/tex]

[tex] = 3[/tex]

semoga menolong

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Mapel : Matematika

Kelas : 10

Materi : Bentuk Akar, Eksponen, Logaritma

Kode soal : 2

Kode kategorisasi : 10.2.1.1

2log 24 + 2log 3 – 2log 9
= 2log (24 . 3 : 9)
= 2log (72 : 9)
= 2log 8
= 2log 2^3
= 3 . 2log 2
= 3 . 1
= 3

Jawaban:

²Log 24 + ²Log3 = ²Log ( 24 x 3 = 62 )

²Log72 – ²Log9 = ²Log ( 72 : 9 = 8 )

jadi = ²Log8 = ²Log2³ = 3 alhasil

Penjelasan:

agar menolong…….

[tex]2 log(24) + 2 log(3) – 2 log(9 ) \\ = 2.76 + 0.95 – 1.90 \\ = 1.81[/tex]
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