Daftar Isi
1. simpangan baku dr data 2, 8, 10, 4, & 6 adalah…
2. simpangan baku dr data 4, 6, 8, 2, 5 adalah…
1. (2+8+10+4+6)/5 = 30/5 = 6
(2-6)^2 + (8-6)^2 + (10-6)^2 + (4-6)^2 + (6-6)^2 / 5 =
16+4+16+4+0 = 40/5 = 8
simpang baku = akar dr 8 = 2,83
2. (4+6+8+2+5) / 5 = 25/5 = 5
(4-5)^2 + (6-5)^2 + (8-5)^2 + (2-5)^2 + (5-5)^2 / 5=
1+1+9+9+0 /5 = 20/5 = 4
simpang baku = akar 4 = 2
simpangan baku dr data 2 4 8 6 10 adalah
rata rata=(4+6+8+2+5)\5=5
s^2=
[ (4-5) ^2+(8-5)^2+(2-5)^2+(5-5)^2]\5
s^2= (1+1+9+9+0)\5
s^2= √4=2
semoga membantu ya
Diketahui suatu data 2 8 10 4 & 6 berapakah simpangan baku dr data tersebut
[tex]xbar = \frac 2 + 8 + 10 + 4 + 6 5 = \frac 30 5 = 6[/tex]
[tex]simpangan \: baku \: = \sqrt \frac (2 – 6) ^ 2 + (8 – 6) ^ 2 + (10 – 6) ^ 2 + (4 – 6) ^ 2 + (6 – 6) ^ 2 5 [/tex]
[tex] = \sqrt \frac 4 ^ 2 + 2 ^ 2 + 4 ^ 2 + 2 ^ 2 + 0 ^ 2 5 [/tex]
[tex] = \sqrt \frac 16 + 4 + 16 + 4 + 0 5 [/tex]
[tex] = \sqrt \frac 40 5 [/tex]
[tex] = \sqrt 20 [/tex]
[tex] = 2 \sqrt 5 [/tex]
Simpangan baku dr data 2 4 8 6 10 adalah
Jawaban:
5 Maaf Kalo Salah
Penjelasan:
- YNTKTS
simpangan baku dr data 2, 8, 10, 4, & 6 adalah ?
SB= 30(7-6) / 5
= 30 (1) / 5
= 6