Sebanyak 100 mL larutan CH₃COOH 0,2 M dicampur dengan 100 mL larutan NaOH 0,2 M.

24/07/2022 by hadi wargamasyarakat

Jika Ka CH₃COOH = 1 × 10⁻⁵, maka pH larutan sesudah diaduk yaitu …

Pembahasan:

mol CH₃COOH = V CH₃COOH × M CH₃COOH

= 100 ml × 0,2 M = 20 mmol

mol NaOH = V NaOH × M NaOH

= 100 ml × 0,2 M = 20 mmol

[OH⁻] = √Kw[garam]

Kₐ

= √Kw . mol

Ka V campuran

= √10⁻¹⁴ . 20 mmol

10⁻⁵ 200 ml

= 10⁻⁵

pOH = – log [10⁻⁵] = 5

PH = 14 – 5 = 9